0.006x^2+0.58x+1.5=0

Solution for 0.006x^2+0.58x+1.5=0 equation:

0.006x^2+0.58x+1.5=0

a = 0.006; b = 0.58; c = +1.5;
Δ = b2-4ac
Δ = 0.582-4·0.006·1.5
Δ = 0.3004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.58)-\sqrt{0.3004}}{2*0.006}=\frac{-0.58-\sqrt{0.3004}}{0.012}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.58)+\sqrt{0.3004}}{2*0.006}=\frac{-0.58+\sqrt{0.3004}}{0.012}
$